QJEEM20Ma4c3b: JEE Main 2020 Mathematics - Class 12 JEEM20Ma4c3b Solution: ∫ − π π

Question

Verified Solution • 2025–26 Session moderate

\int_{- π}^{π} | π - | x | | d x

is equal to :

Accepted Answer

\int_{- π}^{π} | π - | x | | d x

=

2 \int_{0}^{π} | π - | x | | d x

[As it is even function]

=

2 \int_{0}^{π} (π - x) d x

=

2 {[π x - \frac{x^{2}}{2}]}_{0}^{π}

=

π^{2}

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