Verified Solution • 2025–26 Session moderate

QJEEM20Ma4c00: JEE Main 2020 Mathematics - Class 11 JEEM20Ma4c00 Solution: If R = {(x, y) : x, y Z, x 2 + 3y 2 8} is a relation on the set …

If R = {(x, y) : x, y ∈\in Z, x2 + 3y2 ≤\le 8} is a relation on the set of integers Z, then the domain of R–1 is :

Multiple Choice Options

  • A {0, 1}
  • B {–2, –1, 1, 2}
  • C {–1, 0, 1}
  • D {–2, –1, 0, 1, 2}

Step-by-Step Verified Solution

Given R = {(x, y) : x, y ∈\in Z, x2 + 3y2 ≤\le 8}

So R = {(0,1), (0,–1), (1,0), (–1,0), (1,1), (1,-1)
(-1,1), (-1,-1), (2,0), (-2,0), (-2,0), (2,1), (2,-1), (-2,1), (-2,-1)}

⇒\Rightarrow R : { -2, -1, 0, 1, 2} →\to {-1, 0, 1}

∴\therefore R-1 : {-1, 0, 1} →\to { -2, -1, 0, 1, 2}

∴\therefore Domain of R–1 = {-1, 0, 1}

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