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QJEEM20Ma1fad: JEE Main 2020 Mathematics - Class 11 JEEM20Ma1fad Solution: If the co-ordinates of two points A and B are and respectively…

If the co-ordinates of two points A and B
are (7,0)\left( {\sqrt 7 ,0} \right) and (−7,0)\left( { - \sqrt 7 ,0} \right) respectively and
P is any point on the conic, 9x2 + 16y2 = 144, then PA + PB is equal to :

Multiple Choice Options

  • A 8
  • B 9
  • C 16
  • D 6

Step-by-Step Verified Solution

9x2 + 16y2 = 144

⇒\Rightarrow x216+y29=1{{{x^2}} \over {16}} + {{{y^2}} \over 9} = 1

∴\therefore a = 4; b = 3;

Now e = 1−916=74\sqrt {1 - {9 \over {16}}} = {{\sqrt 7 } \over 4}

A and B are foci

PA + PB = 2a = 2 × 4 = 8

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