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QJEEM20Ma1f11: JEE Main 2020 Mathematics - Class 11 JEEM20Ma1f11 Solution: If z be a complex number satisfying

If z be a complex number satisfying |Re(z)| + |Im(z)| = 4, then |z| cannot be :

Multiple Choice Options

  • A 10\sqrt {10}
  • B 7\sqrt {7}
  • C 172\sqrt {{{17} \over 2}}
  • D 8\sqrt {8}

Step-by-Step Verified Solution

Let z = x + iy

given that |Re(z)| + |Im(z)| = 4

∴\therefore |x| + |y| = 4 JEE Main 2020 (Online) 9th January Evening Slot Mathematics - Complex Numbers Question 124 English Explanation
Maximum value of |z| = 4

Minimum value of |z| = perpendicular distance of line AB from (0, 0) = 222\sqrt 2

∴\therefore |z| ∈\in [22,4]\left[ {2\sqrt 2 ,4} \right]

∴\therefore |z| cannot be 7\sqrt {7} .

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