Verified Solution • 2025–26 Session
moderate
QJEEM20Ma13af: JEE Main 2020 Mathematics - Class 11 JEEM20Ma13af Solution: The number of ordered pairs (r, k) for which 6. 35 C r = (k 2 - …
The number of ordered pairs (r, k) for which
6.35Cr = (k2 - 3). 36Cr + 1, where k is an integer, is :
6.35Cr = (k2 - 3). 36Cr + 1, where k is an integer, is :
Multiple Choice Options
- A 6
- B 3
- C 2
- D 4
Step-by-Step Verified Solution
6.35Cr = (k2 - 3). 36Cr + 1
6.35Cr = (k2 - 3). 35Cr
k2 - 3 =
Possible values of r for integral values of k, are
r = 5, 35
number of ordered pairs are 4
(5, 2), (5, –2), (35, 3), (35, 3)
6.35Cr = (k2 - 3). 35Cr
k2 - 3 =
Possible values of r for integral values of k, are
r = 5, 35
number of ordered pairs are 4
(5, 2), (5, –2), (35, 3), (35, 3)