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QJEEM20Ma0bfe: JEE Main 2020 Mathematics - Class 11 JEEM20Ma0bfe Solution: The mean and the standard deviation (s.d.) of 10 observations…

The mean and the standard deviation (s.d.) of 10 observations are 20 and 2 resepectively. Each of these 10 observations is multiplied by p and then reduced by q, where p ≠\ne 0 and q ≠\ne 0. If the new mean and new s.d. become half of their original values, then q is equal to

Multiple Choice Options

  • A 10
  • B -20
  • C -10
  • D -5

Step-by-Step Verified Solution

Let observations are x1, x2, ...., x10

Here mean = 20 and standard deviation(S.D) = 2

When each of these 10 observations is multiplied by p then new observations are px1, px2, ....., px10
and new mean = 20p and new standard deviation(S.D) = 2|p|

Now when Reduced by q then new observations are
px1 - q, px2 - q, ....., px10 - q

and new mean = 20p - q and new standard deviation(S.D) = 2|p|

Given 20p - q = 202{{20} \over 2} = 10
and 2|p| = 22{2 \over 2} = 1

⇒\Rightarrow p = ±\pm 12{1 \over 2}

If p = 12{1 \over 2} then q = 0 (not possible as given q ≠\ne 0)

If p = - 12{1 \over 2} then q = -20

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