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QJEEM20Ma0bfe: JEE Main 2020 Mathematics - Class 11 JEEM20Ma0bfe Solution: The mean and the standard deviation (s.d.) of 10 observations…
The mean and the standard deviation (s.d.) of 10 observations are 20 and 2 resepectively. Each of these 10 observations is multiplied by p and then reduced by q, where p 0 and q 0. If the new mean and new s.d. become half of their original values, then q is equal to
Multiple Choice Options
- A 10
- B -20
- C -10
- D -5
Step-by-Step Verified Solution
Let observations are x1, x2, ...., x10
Here mean = 20 and standard deviation(S.D) = 2
When each of these 10 observations is multiplied by p then new observations are px1, px2, ....., px10
and new mean = 20p and new standard deviation(S.D) = 2|p|
Now when Reduced by q then new observations are
px1 - q, px2 - q, ....., px10 - q
and new mean = 20p - q and new standard deviation(S.D) = 2|p|
Given 20p - q = = 10
and 2|p| = = 1
p =
If p = then q = 0 (not possible as given q 0)
If p = - then q = -20
Here mean = 20 and standard deviation(S.D) = 2
When each of these 10 observations is multiplied by p then new observations are px1, px2, ....., px10
and new mean = 20p and new standard deviation(S.D) = 2|p|
Now when Reduced by q then new observations are
px1 - q, px2 - q, ....., px10 - q
and new mean = 20p - q and new standard deviation(S.D) = 2|p|
Given 20p - q = = 10
and 2|p| = = 1
p =
If p = then q = 0 (not possible as given q 0)
If p = - then q = -20