QJEEM20Chf1d0: JEE Main 2020 Chemistry - Class 11 JEEM20Chf1d0 Solution: The mass of ammonia in grams produced when 2.8 kg of dinitrogen …

N₂(g) + 3H₂(g) $\to$ 2NH₃(g)

Number of moles of N₂ = ${{2.8 \times {{10}^3}} \over {28}}$ = 100

Number of moles of H₂ = ${{1000} \over 2}$ = 500

Here N₂ is limiting reagent.

$\therefore$ Number of moles of NH₃ produced = 2 $\times$ 100 = 200

Mass of NH₃ produced = 200 × 17 = 3400 gm