Verified Solution • 2025–26 Session moderate

QJEEM20Chf101: JEE Main 2020 Chemistry - Class 12 JEEM20Chf101 Solution: For the disproportionation reaction 2Cu + (aq) ⇌ Cu(s) + Cu 2+…

For the disproportionation reaction
2Cu+(aq) ⇌ Cu(s) + Cu2+(aq) at 298 K. ln K
(where K is the equilibrium constant) is
___________ × 10–1.
Given :
( ECu2+/Cu+0=0.16VE_{C{u^{2 + }}/C{u^ + }}^0 = 0.16V
ECu+/Cu0=0.52VE_{C{u^ + }/Cu}^0 = 0.52V
RTF=0.025{{RT} \over F} = 0.025 )

Step-by-Step Verified Solution

Ecell0E_{cell}^0 = ECu+/Cu0E_{C{u^ + }/Cu}^0 - ECu2+/Cu+0E_{C{u^{2 + }}/C{u^ + }}^0

= 0.52 – 0.16

= 0.36 V

At equilibrium, Ecell = 0

Ecell0E_{cell}^0 = RTnF{{RT} \over {nF}} ln K

⇒\Rightarrow ln K = Ecell0×nFRT{{E_{cell}^0 \times nF} \over {RT}}

= 0.36×10.025{{0.36 \times 1} \over {0.025}} = 14.4 = 144 ×\times 10-1

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