Verified Solution • 2025–26 Session moderate

QJEEM20Chdc41: JEE Main 2020 Chemistry - Class 12 JEEM20Chdc41 Solution: 108 g of silver (molar mass 108 g mol –1 ) is deposited at…

108 g of silver (molar mass 108 g mol–1) is deposited at cathode from AgNO3(aq) solution by a certain quantity of electricity. The volume (in L) of oxygen gas produced at 273 K and 1 bar pressure from water by the same quantity of electricity is _______.

Step-by-Step Verified Solution

Cathode : Ag+(aq) + e- →\to Ag(s)

Moles of Ag deposited = 108108{{108} \over {108}} = 1 mole

Anode : 2H2O →\to O2 + 4H+ + 4e-

Here we have to find volume of O2 evolved.

Equivalance of Ag = Equivalance of O2

⇒\Rightarrow 1 ×\times 1 = nO2 ×\times 4

⇒\Rightarrow nO2 = 14{1 \over 4} mol

∴\therefore Volume of O2 evolved

= 14{1 \over 4} ×\times 22.4

= 5.6 lit

Related Learning Resources & Exam Preparation