QJEEM20Chdc18: JEE Main 2020 Chemistry - Class 12 JEEM20Chdc18 Solution: The number of molecules with energy greater than the threshold…

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QJEEM20Chdc18: JEE Main 2020 Chemistry - Class 12 JEEM20Chdc18 Solution: The number of molecules with energy greater than the threshold…

The number of molecules with energy greater than the threshold energy for a reaction increases five fold by a rise of temperature from 27^oC to 42^oC. Its energy of activation in J/mol is _____.
(Take ln 5 = 1.6094; R = 8.314 J mol^–1 K^–1)

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Accepted Answer

∵

k = A

e^{- \frac{E_{a}}{R T}}

T₁ = 300K, T₂ = 315K

As per question K_T₂ = 5K_T₂ as molecules activated are increased five times so K will increases five time.

\ln (\frac{K_{T_{2}}}{K_{T_{1}}})

=

\frac{E_{a}}{R} (\frac{1}{T_{1}} - \frac{1}{T_{2}})

\Rightarrow

ln 5 =

\frac{E_{a}}{R} (\frac{15}{300 \times 315})

\Rightarrow

E_a =

\frac{1.6094 \times 8.314 \times 300 \times 315}{15}

= 84297.47 Joules/mole

QJEEM20Chdc18: JEE Main 2020 Chemistry - Class 12 JEEM20Chdc18 Solution: The number of molecules with energy greater than the threshold…

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