Verified Solution • 2025–26 Session moderate

QJEEM20Chcf34: JEE Main 2020 Chemistry - Class 11 JEEM20Chcf34 Solution: When gypsum is heated to 393 K, it forms :

When gypsum is heated to 393 K, it forms :

Multiple Choice Options

  • A CaSO4 . 0.5H2O
  • B CaSO4 . 5H2O
  • C Dead burnt plaster
  • D Anhydrous CaSO4

Step-by-Step Verified Solution

CaSO4.2H2O (Gypsum) ⟶393K

CaSO4.12H2O(Plaster of paris) + 32H2O

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