QJEEM20Chced1: JEE Main 2020 Chemistry - Class 12 JEEM20Chced1 Solution: The mass of gas adsorbed, x, per unit mass of adsorbate, m, was …

Question

Verified Solution • 2025–26 Session moderate

The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between

\log {x \over m}

and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of

{x \over m}

at a pressure of 4 atm is :
(Given log 3 = 0.4771)

Accepted Answer

According to Freundlich adsorption isotherm, in the median range of pressure

{x \over m} \propto {P^{{1 \over n}}}

\Rightarrow

{x \over m}

= kP

^{{1 \over n}}

....(1)

taking log both sides, we get,

log

{x \over m}

= logk +

{1 \over n}

logP

Here in graph between log

{x \over m}

and logP, slope is

{1 \over n}

and intercepts = log k.

Given, log k = 0.4771

\Rightarrow

k = 3

Slope

{1 \over n}

= 2

put in eq. (1),

{x \over m}

= 3

\times

(4)² = 48

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