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QJEEM20Chcafb: JEE Main 2020 Chemistry - Class 12 JEEM20Chcafb Solution: Potassium chlorate is prepared by the electrolysis of KCl in…

Potassium chlorate is prepared by the electrolysis of KCl in basic solution

6OH- + Cl- → ClO3- + 3H2O + 6e-

If only 60% of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce 10 g of KClO3 using a current of 2 A is_________.

(Given : F = 96,500 C mol–1; molar mass of KCIO3 = 122 g mol–1)

Step-by-Step Verified Solution

For synthesis of 1 mole of ClO3- , 6F of charge is required.

∴ To synthesise 10122 moles of KClO3,

Charge required = 10122×6 F

10122×6=2×t(hr)×360096500×60100

⇒ t(hr) = 965×100122×2×36 = 10.98 hr ≃ 11 Hr

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