QJEEM20Chc714: JEE Main 2020 Chemistry - Class 11 JEEM20Chc714 Solution: In the figure shown below reactant A (represented by square) is …

In the figure, Reactant A is represented by square.
And there are 6 squares. So at equilibrium
[A]_eq = 6

In the figure, Product B is represented by circle.
And there are 11 circles. So at equilibrium
[B]_eq = 11

For reaction, A ⇌ B

K_eq = $$\frac{\left[B\right]}{\left[A\right]}$$ = $$\frac{11}{6}$$ $$\approx$$ 2