QJEEM20Chba9b: JEE Main 2020 Chemistry - Class 12 JEEM20Chba9b Solution: What would be the electrode potential for the given half cell…

Question

Verified Solution • 2025–26 Session moderate

What would be the electrode potential for the given half cell reaction at pH = 5? ______.

2H₂O

\to

O₂ + 4H^$\oplus$ + 4e^– ;

E_{r e d}^{0}

= 1.23 V

(R = 8.314 J mol^–1 K^–1 ; Temp = 298 k;

oxygen under std. atm. pressure of 1 bar)

Accepted Answer

E = E₀ -

\frac{0.0591}{4} \log {[H^{+}]}^{4}

\Rightarrow

E = 1.23 + 0.0591 × pH

\Rightarrow

E = 1.23 + 0.0591 × (5)

\Rightarrow

E = 1.52

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