QJEEM20Chb6c9: JEE Main 2020 Chemistry - Class 11 JEEM20Chb6c9 Solution: A spherical balloon of radius 3 cm containing helium gas has a…

Question

Verified Solution • 2025–26 Session moderate

A spherical balloon of radius 3 cm containing helium gas has
a pressure of 48

\times

10^–3 bar. At the same temperature, the pressure, of a spherical balloon of radius 12 cm containing the
same amount of gas will be ________

\times

10^–6 bar.

Accepted Answer

For gas when temperature and number of moles are constant then we can apply Boyle's law.

According to Boyle's law,

P₁V₁ = P₂V₂

Given, P₁ = 48

\times

10^–3 bar

V₁ =

\frac{4}{3} π {(3)}^{3}

V₂ =

\frac{4}{3} π {(12)}^{3}

P₂ = ?

∴

P₂ =

\frac{P_{1} V_{1}}{V_{2}}

=

\frac{48 \times 10^{- 3} \times {(3)}^{3}}{{(12)}^{3}}

= 7.5

\times

10^-4 = 750

\times

10^-6 bar

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