Verified Solution • 2025–26 Session moderate

QJEEM20Chb3bc: JEE Main 2020 Chemistry - Class 11 JEEM20Chb3bc Solution: The de Broglie wavelength of an electron in the 4th Bohr orbit…

The de Broglie wavelength of an electron in the 4th Bohr orbit is :

Multiple Choice Options

  • A 2 π\pi a0
  • B 6 π\pi a0
  • C 8 π\pi a0
  • D 4 π\pi a0

Step-by-Step Verified Solution

According to Bohr’s model

rn=n2Z×a0{r_n} = {{{n^2}} \over Z} \times {a_0}

Also 2 π\pi rn{r_n} = n λ\lambda

⇒\Rightarrow 2 π\pi n2Z×a0{{{n^2}} \over Z} \times {a_0} = n λ\lambda

⇒\Rightarrow λ\lambda = 2π×nZ×a02\pi \times {n \over Z} \times {a_0}

For n = 4 and Z = 1

⇒\Rightarrow λ\lambda = 8 π\pi a0{a_0}

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