QJEEM20Chb3ac: JEE Main 2020 Chemistry - Class 12 JEEM20Chb3ac Solution: Henry’s constant (in kbar) for four gases α , β , γ and δ in…

Question

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Henry’s constant (in kbar) for four gases

α

,

β

,

γ

and

δ

in water at 298 K is given below :

	$α$	$β$	$γ$	$δ$
K_H	50	2	2 $\times$ 10^-5	0.5

(density of water = 10³ kg m^-3 at 298 K)
This table implies that :

Accepted Answer

(1) On increasing temperature solubility of gases decreases.

(2) 55.5 molal solution of

γ

= 55.5 mol of

P_$γ$ = K_HX_$γ$

= 2

\times

10^-5

\times

\frac{55.5}{55.5 + \frac{1000}{18}}

= 10^–5 K bar

= 10^–2 bar

(3) P_$δ$ = K_HX_$δ$

= 0.5

\times

\frac{55.5}{55.5 + \frac{1000}{18}}

= 250 bar

(4) With temperature, the value of K_H (Henry’s constant) increases and solubility of gas in liquid decreases.

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