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QJEEM20Chabe2: JEE Main 2020 Chemistry - Class 12 JEEM20Chabe2 Solution: An element crystallises in a face-centred cubic (fcc) unit cell …

An element crystallises in a face-centred cubic (fcc) unit cell with cell edge aa . The distance between the centres of two nearest octahedral voids in the crystal lattice is :

Multiple Choice Options

  • A aa
  • B a2{a \over 2}
  • C a2{a \over {\sqrt 2 }}
  • D 2a{\sqrt 2 a}

Step-by-Step Verified Solution

JEE Main 2020 (Online) 5th September Evening Slot Chemistry - Solid State Question 37 English Explanation

Distance between nearest octahedral voids (O.V.)

= (a2)2+(a2)2\sqrt {{{\left( {{a \over 2}} \right)}^2} + {{\left( {{a \over 2}} \right)}^2}} = a2{a \over {\sqrt 2 }}

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