QJEEM20Cha9dd: JEE Main 2020 Chemistry - Class 11 JEEM20Cha9dd Solution: The oxidation states of transition metal atoms in K 2 Cr 2 O 7…

K₂Cr₂O₇

Let oxidation state of Ce

2(+1) + 2x + 7(–2) = 0

$$\Rightarrow$$ x = +6

In K₂Cr₂O₇, Transition metal (Cr) present in +6 oxidation state.

KMnO₄

(+1) + y + 4(–2) = 0
$$\Rightarrow$$ x = +7

In KMnO₄, transition metal (Mn) present in +7 oxidation state.

K₂FeO₄

2(+1) + z + 4(–2) = 0
$$\Rightarrow$$x = +6

In K₂FeO₄, transition metal (Fe) present in +6 oxidation state.

$$\therefore$$ x + y + z = 6 + 7 + 6 = 19