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QJEEM20Ch95dd: JEE Main 2020 Chemistry - Class 12 JEEM20Ch95dd Solution: Which of these will produce the highest yield in Friedel Crafts …

Which of these will produce the highest yield in Friedel Crafts reaction?

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/272bd90e7eacc65b0ebab62c5cac517a1581e77d36d32b122131e9b47ac824f8.webp
  • B https://ik.imagekit.io/novatra/photos/68d39a47d0eb8c5e495bf2e8d4b203f53934715fb4f3239edaef31ca83615af2.webp
  • C https://ik.imagekit.io/novatra/photos/e60c1dfe463bfc6d68b3592336600db2d90771047c3826259414b51d147cda9b.webp
  • D https://ik.imagekit.io/novatra/photos/e061e40cf37d8cbed46d885b6e9c8d3a1ac2c80630a545819f23168434ba039c.webp

Step-by-Step Verified Solution

Friedel-Crafts reaction is an electrophilic substitution reaction. In general, the rate of these reactions is highest when benzene have some electron releasing groups, (i.e. −NH2−OH-\mathrm{NH}_2-\mathrm{OH} ) attached to the nucleus.

JEE Main 2020 (Online) 9th January Morning Slot Chemistry - Haloalkanes and Haloarenes Question 112 English Explanation 1
Lewis acid (anhydrous AlCl3\mathrm{AlCl}_3 ) used in these reactions form an adduct with the ' −NH2-\mathrm{NH}_2 ' or −OH-\mathrm{OH} groups and becomes ineffective.

JEE Main 2020 (Online) 9th January Morning Slot Chemistry - Haloalkanes and Haloarenes Question 112 English Explanation 2
JEE Main 2020 (Online) 9th January Morning Slot Chemistry - Haloalkanes and Haloarenes Question 112 English Explanation 3
withdrawing (deactivating) group, but among the given options, it is most reactive towards Friedel-Crafts reaction.

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