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QJEEM20Ch95b8: JEE Main 2020 Chemistry - Class 11 JEEM20Ch95b8 Solution: The mole fraction of glucose (C 6 H 12 O 6 ) in an aqueous…

The mole fraction of glucose (C6H12O6 ) in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is _______.

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Mole fraction of glucose in aqueous solution = 0.1

Let total mole is 1 mol then mole of glucose will be 0.1 and mole of water will be 0.9.

So mass % of water = 0.9×180.1×180+0.9×18 × 100

= 47.37 ≃ 47

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