Verified Solution • 2025–26 Session moderate

QJEEM20Ch8ab7: JEE Main 2020 Chemistry - Class 11 JEEM20Ch8ab7 Solution: The ammonia (NH 3 ) released on quantitative reaction of 0.6 g…

The ammonia (NH3) released on quantitative reaction of 0.6 g urea (NH2CONH2) with sodium hydroxide (NaOH) can be neutralized by :

Multiple Choice Options

  • A 200 ml of 0.02 N HCl
  • B 100 ml of 0.2 N HCl
  • C 100 ml of 0.1 HCl
  • D 200 ml of 0.4 N HCl

Step-by-Step Verified Solution

NH2CONH2 → NH3

Using Principle of Atom Conservation

2 × moles of urea = 1 × moles of NH3

⇒ 2 × 0.660

⇒ moles of NH3 = 0.02

Also moles of NH3 = moles of HCl, because they react in 1 : 1 ratio.

100 ml of 0.2 N HCl = 100×0.21000 = 0.02 mole of HCl

So option (B) is correct.

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