Verified Solution • 2025–26 Session moderate

QJEEM20Ch7f15: JEE Main 2020 Chemistry - Class 12 JEEM20Ch7f15 Solution: The reaction of H 3 N 3 B 3 Cl 3 (A) with LiBH 4 in…

The reaction of H3N3B3Cl3 (A) with LiBH4 in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to H3N3B3(Me)3. Compounds (B) and (C) respectively, are :

Multiple Choice Options

  • A Borazine and MeBr
  • B Diborane and MeMgBr
  • C Boron nitride and MeBr
  • D Borazine and MeMgBr

Step-by-Step Verified Solution

B3N3H3Cl3(A) + LiBH4 → B3N3H6 (B)

B = inorganic benzene or Borazine

B3N3H3Cl + MeMgBr(C) → B3N3H3(CH3)3 + 3MgBrCl

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