Verified Solution • 2025–26 Session moderate

QJEEM20Ch7cfd: JEE Main 2020 Chemistry - Class 12 JEEM20Ch7cfd Solution: The incorrect statement is :

The incorrect statement is :

Multiple Choice Options

  • A In manganate and permanganate ions, the p-bonding takes place by overlap of p-orbitals of oxygen and d-orbitals of manganese
  • B Manganate ion is green in colour and permanganate ion in purple in colour
  • C Manganate and permanganate ions are paramagnetic
  • D Manganate and permanganate ions are tetrahedral

Step-by-Step Verified Solution

To identify the incorrect statement, let's analyze each option :

Option A : "In manganate and permanganate ions, the π-bonding takes place by overlap of p-orbitals of oxygen and d-orbitals of manganese." This statement is true. In both manganate MnO42−{MnO}_4^{2-} and permanganate MnO4−{MnO}_4^- ions, the manganese atom is in a high oxidation state (+6 and +7, respectively) and forms bonds with oxygen atoms involving the overlap of p-orbitals of oxygen and d-orbitals of manganese.

Option B : "Manganate ion is green in colour and permanganate ion in purple in colour." This statement is true. Manganate ions are indeed green and permanganate ions are purple in aqueous solution.

Option C : "Manganate and permanganate ions are paramagnetic." This statement is incorrect. Both manganate and permanganate ions are diamagnetic, not paramagnetic. In these ions, manganese is in +6 and +7 oxidation states, respectively, and has no unpaired electrons.

Manganate( Mn+6\mathop {Mn}\limits^{ + 6} O4 2–) ,

Mn(25) = [Ar]3d64s2

Mn+6(25) = [Ar]3d1 →\to Paramagnetic

Permanganate ( Mn+7\mathop {Mn}\limits^{ + 7} O4-)

Mn(25) = [Ar]3d64s2

Mn+7(25) = [Ar]3d0 →\to Diamagnetic

Option D : "Manganate and permanganate ions are tetrahedral." This statement is true. Both manganate and permanganate ions have a tetrahedral geometry, with the manganese atom at the center and the four oxygen atoms surrounding it.

Therefore, the incorrect statement is option C.

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