QJEEM20Ch72c4: JEE Main 2020 Chemistry - Class 12 JEEM20Ch72c4 Solution: The Gibbs change (in J) for the given reaction at [Cu 2+ ] =…

The Gibbs change (in J) for the given reaction at
[Cu²⁺] = [Sn²⁺] = 1 M and 298K is :

Cu(s) + Sn²⁺(aq.) $\to$ Cu²⁺(aq.) + Sn(s);

( $E_{S{n^{2 + }}|Sn}^0 = - 0.16\,V$ ,
$E_{C{u^{2 + }}|Cu}^0 = 0.34\,V$ )
Take F = 96500 C mol^–1)