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QJEEM20Ch7262: JEE Main 2020 Chemistry - Class 12 JEEM20Ch7262 Solution: = +0.34 V = -0.76 V Identify the incorrect statement from the…

JEE Main 2020 (Online) 4th September Morning Slot Chemistry - Electrochemistry Question 124 English
ECu2+∣Cu0E_{C{u^{2 + }}|Cu}^0 = +0.34 V

EZn2+∣Zn0E_{Z{n^{2 + }}|Zn}^0 = -0.76 V

Identify the incorrect statement from the option below for the above cell :

Multiple Choice Options

  • A If Eext < 1.1 V, Zn dissolves at anode and Cu deposits at cathode
  • B If Eext = 1.1 V, no flow of e– or current occurs
  • C If Eext > 1.1 V, e– flows from Cu to Zn
  • D If Eext > 1.1 V, Zn dissolves at Zn electrode and Cu deposits at Cu electrode

Step-by-Step Verified Solution

Ecell0E_{cell}^0 = ECu2+∣Cu0E_{C{u^{2 + }}|Cu}^0 - EZn2+∣Zn0E_{Z{n^{2 + }}|Zn}^0

= 0.34 – (–0.76)

= 1.10 V

If Eext < 1.1 V then Zn dissolves at anode and copper deposits at Cathode.

If Eext > 1.1V then Zn deposited at zinc electrodes and Cu deposits at Cu electrode.

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