QJEEM20Ch71dc: JEE Main 2020 Chemistry - Class 11 JEEM20Ch71dc Solution: The variation of equilibrium constant with temperature is given …

Question

Verified Solution • 2025–26 Session moderate

The variation of equilibrium constant with temperature is given below :

Temperature	Equilibrium Constant
T₁ = 25^oC	K₁ = 10
T₂ = 100^oC	K₂ = 100

The values of

Δ

H^o,

Δ

G^o at
T₁ and

Δ

G^o at T₂ (in kJ mol^–1) respectively, are close to :
[Use R = 8.314 J K^–1 mol^–1]

Accepted Answer

ln

[\frac{k_{2}}{k_{1}}]

=

\frac{Δ H^{\circ}}{R} {\frac{1}{T_{1}} - \frac{1}{T_{2}}}

\Rightarrow

ln(10) =

\frac{Δ H^{\circ}}{R} {\frac{1}{298} - \frac{1}{373}}

\Rightarrow

Δ H^{\circ}

= 28.37 kJ/mol

Δ

G^o = –RT ln K

T₁ = 25^oC K₁ = 10

Δ

G^o at T₁ = –8.314 × 298 × 2.303 × log 10

= –5.71 kJ/mol

Δ

G^o at T₂ = –8.314 × 373 × 2.303 × log(100)

= –14.29 kJ/mol

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