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QJEEM20Ch68d8: JEE Main 2020 Chemistry - Class 11 JEEM20Ch68d8 Solution: Of the species, NO, NO + , NO 2+ and NO - , the one with…
Of the species, NO, NO+, NO2+ and NO- , the one with minimum bond strength is :
Multiple Choice Options
- A NO–
- B NO
- C NO+
- D NO2+
Step-by-Step Verified Solution
Note :
(1) Bond strength Bond order
(2) Bond length
(3) Bond order [Nb Na]
Nb = No of electrons in bonding molecular orbital
Na No of electrons in anti bonding molecular orbital
(4) upto 14 electrons, molecular orbital configuration is
Here Na = Anti bonding electron 4 and Nb = 10
(5) After 14 electrons to 20 electrons molecular orbital configuration is - - -
Molecular orbital configuration of NO (15 electrons) is
Nb = 10
Na = 5
BO = = 2.5
Similarly Molecular orbital configuration of NO+ (14 electrons) is
Nb = 10
Na = 4
BO = = 3
Similarly Molecular orbital configuration of NO2+ (13 electrons) is
Nb = 9
Na = 4
BO = = 2.5
Molecular orbital configuration of NO- (16 electrons) is
Nb = 10
Na = 6
BO = = 2
As Bond strength Bond order
NO– will have minimum bond strength.
(1) Bond strength Bond order
(2) Bond length
(3) Bond order [Nb Na]
Nb = No of electrons in bonding molecular orbital
Na No of electrons in anti bonding molecular orbital
(4) upto 14 electrons, molecular orbital configuration is
Here Na = Anti bonding electron 4 and Nb = 10
(5) After 14 electrons to 20 electrons molecular orbital configuration is - - -
Molecular orbital configuration of NO (15 electrons) is
Nb = 10
Na = 5
BO = = 2.5
Similarly Molecular orbital configuration of NO+ (14 electrons) is
Nb = 10
Na = 4
BO = = 3
Similarly Molecular orbital configuration of NO2+ (13 electrons) is
Nb = 9
Na = 4
BO = = 2.5
Molecular orbital configuration of NO- (16 electrons) is
Nb = 10
Na = 6
BO = = 2
As Bond strength Bond order
NO– will have minimum bond strength.