Verified Solution • 2025–26 Session
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QJEEM20Ch5f9b: JEE Main 2020 Chemistry - Class 12 JEEM20Ch5f9b Solution: The increasing order of basicity of the following compounds is :
The increasing order of basicity of the following compounds is : 
Multiple Choice Options
- A (A) < (B) < (C) < (D)
- B (B) < (A) < (C) < (D)
- C (D) < (A) < (B) < (C)
- D (B) < (A) < (D) < (C)
Step-by-Step Verified Solution
The compound which can donate lone pair more easily is more basic.
(A) N is sp2 hybridized and lone pair is localised means not perticipating in resonance.
(B) Here lone pair perticipates in resonance and involved in aromaticity. So this is weakest base.
(C) N is sp3 hybridized and lone pair is localised means not perticipating in resonance. As here N atom is sp3 hybridized so it is more basic than A and D.
(D) Here lone pair of 1st N atom perticipates in resonance but 2nd N is sp2 hybridized and lone pair is localised means not perticipating in resonance. So basisity will depend on 2nd N atom. Due to perticipatation in resonance of 1st N atom some negative charge is genareted on 2nd N atom which makes it more basic than compound A.
(A) N is sp2 hybridized and lone pair is localised means not perticipating in resonance.
(B) Here lone pair perticipates in resonance and involved in aromaticity. So this is weakest base.
(C) N is sp3 hybridized and lone pair is localised means not perticipating in resonance. As here N atom is sp3 hybridized so it is more basic than A and D.
(D) Here lone pair of 1st N atom perticipates in resonance but 2nd N is sp2 hybridized and lone pair is localised means not perticipating in resonance. So basisity will depend on 2nd N atom. Due to perticipatation in resonance of 1st N atom some negative charge is genareted on 2nd N atom which makes it more basic than compound A.