Verified Solution • 2025–26 Session
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QJEEM20Ch5826: JEE Main 2020 Chemistry - Class 12 JEEM20Ch5826 Solution: 250 mL of a waste solution obtained from the workshop of a…
250 mL of a waste solution obtained from the workshop of a goldsmith contains 0.1 M AgNO3 and 0.1 M AuCl. The solution was electrolyzed at 2V by passing a current of 1A for 15 minutes. The metal/metals electrodeposited will be
[ = 0.80 V, = 1.69 V ]
[ = 0.80 V, = 1.69 V ]
Multiple Choice Options
- A Silver and gold in equal mass proportion
- B Silver and gold in proportion to their atomic weights
- C Only gold
- D Only silver
Step-by-Step Verified Solution
Millimoles of Au+ = 0.1 × 250 = 25
Mole of Au+ = =
Charge passed = I × t = 1 × 15 × 60 = 900 C
moles of e– passed = =
Only gold will be deposited as quantity of charge passed is less than the amount of Au+ present.
Mole of Au+ = =
Charge passed = I × t = 1 × 15 × 60 = 900 C
moles of e– passed = =
Only gold will be deposited as quantity of charge passed is less than the amount of Au+ present.