Verified Solution • 2025–26 Session moderate

QJEEM20Ch5823: JEE Main 2020 Chemistry - Class 12 JEEM20Ch5823 Solution: The osmotic pressure of a solution of NaCl is 0.10 atm and that …

The osmotic pressure of a solution of NaCl is 0.10 atm and that of a glucose solution is 0.20 atm. The osmotic pressure of a solution formed by mixing 1 L of the sodium chloride solution with 2 L of
the glucose solution is x ×\times 10–3 atm. x is _____. (nearest integer)

Step-by-Step Verified Solution

For NaCl : π\pi 1 = 0.1 atm, v1 = 1 L

For Glucose: π\pi 2 = 0.2 atm, v2 = 2 L

π\pi mix = π1v1+π2v2v1+v2{{{\pi _1}{v_1} + {\pi _2}{v_2}} \over {{v_1} + {v_2}}}

= 0.1×1+0.2×21+2{{0.1 \times 1 + 0.2 \times 2} \over {1 + 2}}

= 0.53{{0.5} \over 3} = 5003×10−3{{500} \over 3} \times {10^{ - 3}}

= 167 ×\times 10-3 atm

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