Verified Solution • 2025–26 Session moderate

QJEEM20Ch528b: JEE Main 2020 Chemistry - Class 11 JEEM20Ch528b Solution: In Carius method of estimation of halogen, 0.172 g of an…

In Carius method of estimation of halogen, 0.172 g of an organic compound showed presence of 0.08 g of bromine. Which of these is the correct structure of the compound?

Multiple Choice Options

  • A H3C – CH2 – Br
  • B H3C – Br
  • C 0
  • D 0

Step-by-Step Verified Solution

In Carius method
mass of organic compound = 0.172 gm
mass of Bromine = 0.08 gm

Hence % of Bromine = 0.080.172×100{{0.08} \over {0.172}} \times 100

= 46.51 %

Option (A) Br mass % = 80109×100{{80} \over {109}} \times 100 = 73.33%

(B) Br mass % = 8095×100{{80} \over {95}} \times 100 = 84.2 %

(C) Br mass % = 80172×100{{80} \over {172}} \times 100 = 46.51 %

(D) Br mass % = 80×2252×100{{80 \times 2} \over {252}} \times 100 = 63.49 %

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