QJEEM20Ch5074: JEE Main 2020 Chemistry - Class 11 JEEM20Ch5074 Solution: The first and second ionisation enthalpies of a metal are 496…

First ionization enthalpies = 496 kJ/mole

Second ionization enthalpies = 4560 kJ/mol

According to the given information, the difference between first and second ionization enthalpy is very high so Metal belong to 1st group i.e. Monovalent cation.

Metal hydroxide will be of type, MOH.

MOH + HCl $$\to$$ MCl + H₂O

MOH + $$\frac{1}{2}$$H₂SO₄ $$\to$$ $$\frac{1}{2}$$M₂SO₄ + H₂O

So one mole of HCl required to react with one mole MOH.

And $$\frac{1}{2}$$ mole of H₂SO₄ required to react with one mole MOH.