Verified Solution • 2025–26 Session moderate

QJEEM20Ch4d00: JEE Main 2020 Chemistry - Class 11 JEEM20Ch4d00 Solution: The volume, in mL, of 0.02 M K 2 Cr 2 O 7 solution required to…

The volume, in mL, of 0.02 M K2Cr2O7 solution required to react with 0.288 g of ferrous oxalate in acidic medium is _______.
(Molar mass of Fe = 56 g mol–1)

Step-by-Step Verified Solution

K2Cr2O7 + FeC2O4 →\to Cr+3 + Fe+3 + CO2

nfactor of K2Cr2O7 = 3 ×\times 2 = 6

nfactor of FeC2O4 = 1 + 2 = 3

m. eq. of K2Cr2O7 = m. eq. of FeC2O4

⇒\Rightarrow 6×0.02×vol1000{{6 \times 0.02 \times vol} \over {1000}} = 0.288144×3{{0.288} \over {144}} \times 3

⇒\Rightarrow vol = 50 ml

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