QJEEM20Ch3cee: JEE Main 2020 Chemistry - Class 11 JEEM20Ch3cee Solution: The value of K C is 64 at 800 K for the reaction N 2 (g) + 3H 2 …

Question

Verified Solution • 2025–26 Session moderate

The value of K_C is 64 at 800 K for the reaction

N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

The value of K_C for the following reaction is :

NH₃(g) ⇌

\frac{1}{2}

N₂(g) +

\frac{3}{2}

H₂(g)

Accepted Answer

N₂(g) + 3H₂(g) ⇌ 2NH₃(g) ; K_C

2NH₃(g) ⇌ N₂(g) + 3H₂(g) ;

\frac{1}{K_{C}}

Multiplying by

\frac{1}{2}

, reaction becomes

NH₃(g) ⇌

\frac{1}{2}

N₂(g) +

\frac{3}{2}

H₂(g) ;

∴

New K_C =

{(\frac{1}{K_{C}})}^{\frac{1}{2}}

=

{(\frac{1}{64})}^{\frac{1}{2}}

=

\frac{1}{8}

Step-by-Step Verified Solution