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QJEEM20Ch1e58: JEE Main 2020 Chemistry - Class 11 JEEM20Ch1e58 Solution: For the Balmer series in the spectrum of H atom, , the correct…
For the Balmer series in the spectrum of H atom,
, the correct statements among (I) to (IV) are :
(I) As wavelength decreases, the lines in the series converge
(II) The integer n1 is equal to 2
(III) The lines of longest wavelength corresponds to n2 = 3
(IV) The ionization energy of hydrogen can be calculated from wave number of these lines
, the correct statements among (I) to (IV) are :
(I) As wavelength decreases, the lines in the series converge
(II) The integer n1 is equal to 2
(III) The lines of longest wavelength corresponds to n2 = 3
(IV) The ionization energy of hydrogen can be calculated from wave number of these lines
Multiple Choice Options
- A (II), (III), (IV)
- B (I), (II), (III)
- C (I), (III), (IV)
- D (I), (II), (IV)
Step-by-Step Verified Solution
For balmer series : n1 = 2, n2 = 3, 4, 5, .....
For longest wavelength n2 = 3
As wavelength decreases the lines in the Balmer series converge. The correct statements are (I), (II) and (III).
For longest wavelength n2 = 3
As wavelength decreases the lines in the Balmer series converge. The correct statements are (I), (II) and (III).