Verified Solution • 2025–26 Session
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QJEEM20Ch1d63: JEE Main 2020 Chemistry - Class 11 JEEM20Ch1d63 Solution: Arrange the following solutions in the decreasing order of pOH…
Arrange the following solutions in the decreasing order of pOH :
(A) 0.01 M HCl
(B) 0.01 M NaOH
(C) 0.01 M CH3COONa
(D) 0.01 M NaCl
(A) 0.01 M HCl
(B) 0.01 M NaOH
(C) 0.01 M CH3COONa
(D) 0.01 M NaCl
Multiple Choice Options
- A (B) > (C) > (D) > (A)
- B (A) > (D) > (C) > (B)
- C (A) > (C) > (D) > (B)
- D (B) > (D) > (C) > (A)
Step-by-Step Verified Solution
(A) 10–2 M HCl [H+] = 10–2 M pH = 2 pOH = 14 - 2 = 12
(B) 10–2 M NaOH [OH–] = 10–2 M pOH = 2
(C) 10–2 M CH3COO–Na+ [OH+] > 10–7 pOH < 7
(D) 10–2 M NaCl Neutral pOH = 7
Order of pOH value A > D > C > B
(B) 10–2 M NaOH
(C) 10–2 M CH3COO–Na+
(D) 10–2 M NaCl
Order of pOH value A > D > C > B