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QJEEM20Ch1c08: JEE Main 2020 Chemistry - Class 11 JEEM20Ch1c08 Solution: For a reaction X + Y ⇌ 2Z , 1.0 mol of X, 1.5 mol of Y and 0.5…

For a reaction X + Y ⇌ 2Z , 1.0 mol of X, 1.5 mol
of Y and 0.5 mol of Z were taken in a 1 L vessel and
allowed to react. At equilibrium, the concentration
of Z was 1.0 mol L–1. The equilibrium constant of reaction
is x15{x \over {15}} . The value of x is _________.

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JEE Main 2020 (Online) 5th September Evening Slot Chemistry - Chemical Equilibrium Question 63 English Explanation

Keq = (1)234×54{{{{\left( 1 \right)}^2}} \over {{3 \over 4} \times {5 \over 4}}} = 1615{{16} \over {15}}

∴\therefore x = 16

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