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QJEEM20Ch1637: JEE Main 2020 Chemistry - Class 11 JEEM20Ch1637 Solution: B has a smaller first ionization enthalpy than Be. Consider the …
B has a smaller first ionization enthalpy than Be. Consider the following statements :
(I) It is easier to remove 2p electron than 2s electron
(II) 2p electron of B is more shielded from the nucleus by the inner core of electrons than the 2s electrons of Be.
(III) 2s electron has more penetration power than 2p electron.
(IV) atomic radius of B is more than Be (Atomic number B = 5, Be = 4)
The correct statements are :
(I) It is easier to remove 2p electron than 2s electron
(II) 2p electron of B is more shielded from the nucleus by the inner core of electrons than the 2s electrons of Be.
(III) 2s electron has more penetration power than 2p electron.
(IV) atomic radius of B is more than Be (Atomic number B = 5, Be = 4)
The correct statements are :
Multiple Choice Options
- A (I), (III) and (IV)
- B (II), (III) and (IV)
- C (I), (II) and (IV)
- D (I), (II) and (III)
Step-by-Step Verified Solution
1st I.E. of Be > B
In case of Be, electron is removed from 2s orbital which has more penetration power, while in case of B electron is removed from 2p orbital which has less penetration power.
2p electron of B is more shielded from nucleus by the inner electrons than 2s electrons of Be
It is easier to remove 2p electron than 2s electron.
In case of Be, electron is removed from 2s orbital which has more penetration power, while in case of B electron is removed from 2p orbital which has less penetration power.
2p electron of B is more shielded from nucleus by the inner electrons than 2s electrons of Be
It is easier to remove 2p electron than 2s electron.