Verified Solution • 2025–26 Session moderate

QJEEM20Ch11be: JEE Main 2020 Chemistry - Class 12 JEEM20Ch11be Solution: For the reaction 2A + 3B + C 3P, which statement is correct ?

For the reaction
2A + 3B + 32{3 \over 2} C →\to 3P, which statement is correct ?

Multiple Choice Options

  • A dnAdt=dnBdt=dnCdt{{d{n_A}} \over {dt}} = {{d{n_B}} \over {dt}} = {{d{n_C}} \over {dt}}
  • B dnAdt=23dnBdt=34dnCdt{{d{n_A}} \over {dt}} = {2 \over 3}{{d{n_B}} \over {dt}} = {3 \over 4}{{d{n_C}} \over {dt}}
  • C dnAdt=32dnBdt=34dnCdt{{d{n_A}} \over {dt}} = {3 \over 2}{{d{n_B}} \over {dt}} = {3 \over 4}{{d{n_C}} \over {dt}}
  • D dnAdt=23dnBdt=43dnCdt{{d{n_A}} \over {dt}} = {2 \over 3}{{d{n_B}} \over {dt}} = {4 \over 3}{{d{n_C}} \over {dt}}

Step-by-Step Verified Solution

2A + 3B + 32{3 \over 2} C →\to 3P

rate = −12d[A]dt=−13d[B]dt=−23d[C]dt=13d[P]dt- {1 \over 2}{{d\left[ A \right]} \over {dt}} = - {1 \over 3}{{d\left[ B \right]} \over {dt}} = - {2 \over 3}{{d\left[ C \right]} \over {dt}} = {1 \over 3}{{d\left[ P \right]} \over {dt}}

⇒\Rightarrow d[A]dt=23d[B]dt=43d[C]dt{{d\left[ A \right]} \over {dt}} = {2 \over 3}{{d\left[ B \right]} \over {dt}} = {4 \over 3}{{d\left[ C \right]} \over {dt}} =−23d[P]dt= - {2 \over 3}{{d\left[ P \right]} \over {dt}}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring