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QJEEM20Ch10ce: JEE Main 2020 Chemistry - Class 12 JEEM20Ch10ce Solution: Complex A has a composition of H 12 O 6 Cl 3 Cr. If the complex …
Complex A has a composition of H12O6Cl3Cr. If the complex on treatment with conc.H2SO4 loses 13.5% of its original mass, the correct molecular formula of A is :
[Given: atomic mass of Cr = 52 amu and Cl = 35 amu]
[Given: atomic mass of Cr = 52 amu and Cl = 35 amu]
Multiple Choice Options
- A [Cr(H2O)5Cl]Cl2.H2O
- B [Cr(H2O)4Cl2]Cl.2H2O
- C [Cr(H2O)3Cl3].3H2O
- D [Cr(H2O)6]Cl3
Step-by-Step Verified Solution
Let x molecule of water are lost then
13.5 =
x = 1.99 2
Around two moles of water are lost during heating.
Formula of complex could be
[Cr(H2O)4Cl2]Cl.2H2O
13.5 =
[Cr(H2O)4Cl2]Cl.2H2O