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QJEEM19Phf7f2: JEE Main 2019 Physics - Class 11 JEEM19Phf7f2 Solution: The pitch and the number of divisions, on the circular scale,…
The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line.
The readings of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is :
The readings of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is :
Multiple Choice Options
- A 5.755 mm
- B 5.950 mm
- C 5.725 mm
- D 5.740 mm
Step-by-Step Verified Solution
We know,
Least count (LC) =
= 0.5
Reading = MSR + CSR
Given, Main scale reading (MSR) = 5.5 mm
Circular scale reading (CSR)
= 48
= 0.24
As zero of its circular scale lines 3 division below the mean line, it means error is position error.
= 3
= 0.015 mm
= 5.725 mm
Least count (LC) =
= 0.5
Reading = MSR + CSR
Given, Main scale reading (MSR) = 5.5 mm
Circular scale reading (CSR)
= 48
= 0.24
As zero of its circular scale lines 3 division below the mean line, it means error is position error.
= 3
= 0.015 mm
= 5.725 mm