QJEEM19Phf4b4: JEE Main 2019 Physics - Class 12 JEEM19Phf4b4 Solution: The output of the given logic circuit is :

Question

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The output of the given logic circuit is :

JEE Main 2019 (Online) 12th January Morning Slot Physics - Semiconductor Question 158 English

Accepted Answer

Y

= \overset{―}{(\overset{―}{A} + \overset{―}{B}) \overset{―}{A}}

= \overset{―}{\overset{―}{A} + \overset{―}{A} B}

= A (\overset{―}{\overset{―}{A} B})

= A (A + \overset{―}{B})

= A + A \overset{―}{B} = A \overset{―}{B}

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