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QJEEM19Phf409: JEE Main 2019 Physics - Class 12 JEEM19Phf409 Solution: A power transmission line feeds input power at 2300 V to a srep …

A power transmission line feeds input power at 2300 V to a srep down transformer with its primary windings having 4000 turns. The output power is delivered at 230 V by the transformer. If the current in the primary of the transformer is 5A and its efficiency is 90%, the output current would be :

Multiple Choice Options

  • A 50 A
  • B 45 A
  • C 35 A
  • D 25 A

Step-by-Step Verified Solution

Given,

Primary voltage (VP) = 2300 V

Primary current (IP) = 5A

Secondary voltage (VS) = 230 V

efficiency (η) = 90%

We know,

Efficiency (η) = SecondaryPowerPrimaryPower

∴   η = PSPP = VSISVPIP

⇒   0.9 = 230×IS2300×5

⇒   I = 45 A

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