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QJEEM19Phf340: JEE Main 2019 Physics - Class 12 JEEM19Phf340 Solution: The reverse breakdown voltage of a Zener diode is 5.6 V in the…

The reverse breakdown voltage of a Zener diode is 5.6 V in the given circuit.

The current IZ through the Zener is : JEE Main 2019 (Online) 8th April Morning Slot Physics - Semiconductor Question 156 English

Multiple Choice Options

  • A 7 mA
  • B 17 mA
  • C 15mA
  • D 10 mA

Step-by-Step Verified Solution

9 = Vz + VR1

VZ = 5.6 V

VR1 = 9 - 5.6

VR1 = 3.4

IR1=VR1R=3.4200;IR1=17mA

Vz = VR2 = IR2 (R2 )

5.6700=IR2;     IR2=7mA

Iz = (17 – 7) mA = 10 mA

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