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QJEEM19Phf215: JEE Main 2019 Physics - Class 12 JEEM19Phf215 Solution: The truth table for the circuit given in the fig. is:

The truth table for the circuit given in the fig. is: JEE Main 2019 (Online) 12th April Morning Slot Physics - Semiconductor Question 150 English

Multiple Choice Options

  • A |ABY001011101111|
  • B |ABY001010100110|
  • C |ABY001011100110|
  • D |ABY000010101111|

Step-by-Step Verified Solution

C = A + B
and y = A.C―

A B C=(A+B) A.C. y=A.C―
0 0 0 0 1
0 1 1 0 1
1 0 1 1 0
1 1 1 1 0

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