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QJEEM19Phee3a: JEE Main 2019 Physics - Class 12 JEEM19Phee3a Solution: In a photoelectric effect experiment the threshold wavelength…

In a photoelectric effect experiment the threshold wavelength of the light is 380 nm. If the wavelentgh of incident light is 260 nm, the maximum kinetic energy of emitted electrons will be:
Given E (in eV) = 1237/λ (in nm)

Multiple Choice Options

  • A 4.5 eV
  • B 15.1 eV
  • C 3.0 eV
  • D 1.5 eV

Step-by-Step Verified Solution

Kmax=hcλ−hcλo

⇒Kmax=hc(λo−λλλo)

⇒Kmax=(1237)(380−260380×260) = 1.5 eV

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