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QJEEM19Phe8c2: JEE Main 2019 Physics - Class 12 JEEM19Phe8c2 Solution: In an experiment, the resistance of a material is plotted as a…

In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line. One may conclude that : JEE Main 2019 (Online) 10th April Morning Slot Physics - Current Electricity Question 237 English

Multiple Choice Options

  • A R(T)=R0e−T2/T02R(T) = {R_0}{e^{ - {T^2}/T_0^2}}
  • B R(T)=R0T2R(T) = {{{R_0}} \over {{T^2}}}
  • C R(T)=R0eT2/T02R(T) = {R_0}{e^{ {T^2}/T_0^2}}
  • D R(T)=R0e−T02/T2R(T) = {R_0}{e^{ - T_0^2/{T^2}}}

Step-by-Step Verified Solution

1T21T02+ln⁡ R(T)ln⁡ R(To)=1{{{1 \over {{T^2}}}} \over {{1 \over {T_0^2}}}} + {{\ln \,R\left( T \right)} \over {\ln \,R\left( {{T_o}} \right)}} = 1

⇒\Rightarrow ln R(T) = ln R(To) (1−To2T2)\left( {1 - {{T_o^2} \over {{T^2}}}} \right)

R(T)=Roe−(To2T2)R(T) = {R_o}{e^{ - \left( {{{T_o^2} \over {{T^2}}}} \right)}}

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