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QJEEM19Phe6bd: JEE Main 2019 Physics - Class 11 JEEM19Phe6bd Solution: Half mole of an ideal monoatomic gas is heated at constant…

Half mole of an ideal monoatomic gas is heated at constant pressure of 1 atm from 20oC to 90oC. Work done by gas is close to – (Gas constant R = 8.31 J/mol.K)

Multiple Choice Options

  • A 581 J
  • B 73 J
  • C 146 J
  • D 291 J

Step-by-Step Verified Solution

WD = P Δ\Delta V = nR Δ\Delta T = 12×8.31×70{1 \over 2} \times 8.31 \times 70

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